Add comprehensive LeetCode solutions index documentation
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85
src/exercises/2.add-two-numbers.py
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85
src/exercises/2.add-two-numbers.py
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from string import *
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from re import *
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from datetime import *
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from collections import *
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from heapq import *
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from bisect import *
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from copy import *
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from math import *
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from random import *
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from statistics import *
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from itertools import *
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from functools import *
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from operator import *
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from io import *
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from sys import *
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from json import *
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from builtins import *
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import string
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import re
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import datetime
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import collections
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import heapq
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import bisect
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import copy
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import math
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import random
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import statistics
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import itertools
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import functools
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import operator
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import io
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import sys
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import json
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from typing import *
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# @leet start
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# Definition for singly-linked list.
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# class ListNode:
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# def __init__(self, val=0, next=None):
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# self.val = val
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# self.next = next
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class Solution:
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def node(self, val, next=None):
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self.val = val
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self.next = next
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def addTwoNumbers(
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self, l1: Optional[ListNode], l2: Optional[ListNode]
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) -> Optional[ListNode]:
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carry = 0
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value_l1 = l1
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value_l2 = l2
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head = None
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tail = None
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while value_l1 or value_l2:
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l2_val = l2.val if l2 else 0
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l1_val = l1.val if l1 else 0
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addition = l1_val + l2_val + carry
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if addition > 9:
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temp = str(addition)
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carry = int(temp[0])
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addition = int(temp[1])
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else:
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carry = 0
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new_node = ListNode(addition)
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if head is None:
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head = new_node
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tail = new_node
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else:
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tail.next = new_node
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tail = new_node
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value_l1 = l1.next if l1 else None
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value_l2 = l2.next if l2 else None
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l1 = l1.next if l1 else None
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l2 = l2.next if l2 else None
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if carry > 0:
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new_node = ListNode(carry)
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tail.next = new_node
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tail = new_node
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return head
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# @leet end
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