Add comprehensive LeetCode solutions index documentation
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60
src/exercises/2053.kth-distinct-string-in-an-array.py
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60
src/exercises/2053.kth-distinct-string-in-an-array.py
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# @leet imports start
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from string import *
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from re import *
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from datetime import *
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from collections import *
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from heapq import *
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from bisect import *
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from copy import *
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from math import *
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from random import *
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from statistics import *
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from itertools import *
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from functools import *
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from operator import *
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from io import *
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from sys import *
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from json import *
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from builtins import *
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import string
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import re
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import datetime
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import collections
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import heapq
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import bisect
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import copy
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import math
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import random
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import statistics
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import itertools
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import functools
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import operator
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import io
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import sys
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import json
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from typing import *
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# @leet imports end
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# @leet start
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class Solution:
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def kthDistinct(self, arr: List[str], k: int) -> str:
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disc = {}
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banW = []
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for w in arr:
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if w not in disc and w not in banW:
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disc[w] = 1
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else:
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if w not in banW:
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banW.append(w)
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del disc[w]
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arr = list(disc.keys())
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if k > len(arr):
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return ""
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return arr[k - 1]
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# @leet end
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