Add comprehensive LeetCode solutions index documentation
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98
src/exercises/36.valid-sudoku.py
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98
src/exercises/36.valid-sudoku.py
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from string import *
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from re import *
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from datetime import *
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from collections import *
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from heapq import *
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from bisect import *
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from copy import *
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from math import *
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from random import *
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from statistics import *
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from itertools import *
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from functools import *
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from operator import *
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from io import *
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from sys import *
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from json import *
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from builtins import *
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import string
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import re
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import datetime
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import collections
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import heapq
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import bisect
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import copy
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import math
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import random
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import statistics
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import itertools
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import functools
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import operator
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import io
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import sys
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import json
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from typing import *
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# @leet start
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class Solution:
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def isValidSudoku(self, board: List[List[str]]) -> bool:
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rows = [{} for _ in range(len(board))]
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square = [{} for _ in range(len(board))]
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for i in range(len(board)):
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cols = {}
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for j in range(len(board[i])):
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val = board[i][j]
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if val != ".":
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if val in cols:
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return False
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cols[val] = j
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if val in rows[j]:
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return False
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rows[j][val] = i
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if i < 3:
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if j < 3:
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if val in square[0]:
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return False
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square[0][val] = i
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elif j > 2 and j < 6:
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if val in square[1]:
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return False
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square[1][val] = i
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elif j > 5:
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if val in square[2]:
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return False
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square[2][val] = i
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elif i > 2 and i < 6:
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if j < 3:
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if val in square[3]:
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return False
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square[3][val] = i
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elif j > 2 and j < 6:
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if val in square[4]:
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return False
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square[4][val] = i
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elif j > 5:
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if val in square[5]:
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return False
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square[5][val] = i
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elif i > 5:
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if j < 3:
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if val in square[6]:
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return False
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square[6][val] = i
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elif j > 2 and j < 6:
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if val in square[7]:
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return False
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square[7][val] = i
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elif j > 5:
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if val in square[8]:
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return False
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square[8][val] = i
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return True
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# @leet end
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