4.9 KiB
Group Anagrams
Problem Number: 49 Difficulty: Medium Category: Array, Hash Table, String, Sorting LeetCode Link: https://leetcode.com/problems/group-anagrams/
Problem Description
Given an array of strings strs, group the anagrams together. You can return the answer in any order.
An Anagram is a word or phrase formed by rearranging the letters of a different word or phrase, typically using all the original letters exactly once.
Example 1:
Input: strs = ["eat","tea","tan","ate","nat","bat"]
Output: [["bat"],["nat","tan"],["ate","eat","tea"]]
Example 2:
Input: strs = [""]
Output: [[""]]
Example 3:
Input: strs = ["a"]
Output: [["a"]]
Constraints:
1 <= strs.length <= 10^40 <= strs[i].length <= 100strs[i]consists of lowercase English letters
My Approach
I used a Hash Table approach with sorted string keys. The key insight is to use the sorted version of each string as a key to group anagrams together, since anagrams have the same characters when sorted.
Algorithm:
- Handle edge case: if array has less than 2 elements, return the array as is
- Create a hash map to store groups of anagrams
- For each string, sort its characters to create a key
- Use the sorted string as key and group original strings together
- Return all groups from the hash map
Solution
The solution uses a hash table with sorted string keys to group anagrams. See the implementation in the solution file.
Key Points:
- Uses hash table to group anagrams efficiently
- Sorts characters of each string to create unique keys
- Handles edge cases like empty array or single element
- Groups strings with same sorted representation together
- Returns all groups in any order
Time & Space Complexity
Time Complexity: O(n × k log k)
- n is the number of strings
- k is the maximum length of any string
- Sorting each string takes O(k log k) time
- Total: O(n × k log k)
Space Complexity: O(n × k)
- Hash table stores all strings
- Each string can be up to length k
- Total: O(n × k)
Key Insights
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Sorted String as Key: Anagrams have the same characters when sorted, making them perfect keys for grouping.
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Hash Table Efficiency: Using a hash table provides O(1) average time for insertions and lookups.
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Edge Case Handling: Arrays with less than 2 elements can be returned directly.
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Character Sorting: Sorting characters creates a canonical representation for anagrams.
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Grouping Strategy: All strings with the same sorted representation are anagrams of each other.
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Flexible Output: The problem allows returning groups in any order.
Mistakes Made
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Inefficient Key Generation: Initially might use character frequency counting instead of sorting.
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Wrong Data Structure: Not using a hash table for efficient grouping.
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Edge Case Missing: Not properly handling arrays with single elements or empty strings.
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Complex Logic: Overcomplicating the grouping process.
Related Problems
- Valid Anagram (Problem 242): Check if two strings are anagrams
- Find All Anagrams in a String (Problem 438): Find all anagrams of a pattern in a string
- Longest Common Prefix (Problem 14): Find common prefix among strings
- Group Shifted Strings (Problem 249): Group strings that can be shifted to each other
Alternative Approaches
- Character Frequency: Use character count arrays as keys - O(n × k) time
- Prime Number Product: Use product of prime numbers for each character - O(n × k) time
- Bit Manipulation: Use bit masks for character representation (limited to 26 characters)
Common Pitfalls
- Wrong Key Generation: Not using sorted strings or character frequency as keys.
- Inefficient Sorting: Sorting strings repeatedly instead of using efficient key generation.
- Edge Cases: Not handling arrays with single elements or empty strings.
- Memory Usage: Not considering the space complexity of storing all strings.
- Output Format: Not returning the correct nested array structure.
Note: This is a classic hash table problem that demonstrates efficient grouping using sorted string keys.