style(lint): re-format modules/@angular

This commit is contained in:
Alex Eagle
2016-06-08 16:38:52 -07:00
parent bbed364e7b
commit f39c9c9e75
589 changed files with 21829 additions and 24259 deletions

View File

@ -1,51 +1,39 @@
import {
AsyncTestCompleter,
beforeEach,
ddescribe,
xdescribe,
describe,
expect,
iit,
inject,
beforeEachProviders,
it,
xit
} from '@angular/core/testing/testing_internal';
import {AsyncTestCompleter, beforeEach, beforeEachProviders, ddescribe, describe, expect, iit, inject, it, xdescribe, xit} from '@angular/core/testing/testing_internal';
import {Tree, TreeNode} from '../src/segments';
export function main() {
describe('tree', () => {
it("should return the root of the tree", () => {
it('should return the root of the tree', () => {
let t = new Tree<any>(new TreeNode<number>(1, []));
expect(t.root).toEqual(1);
});
it("should return the parent of a node", () => {
it('should return the parent of a node', () => {
let t = new Tree<any>(new TreeNode<number>(1, [new TreeNode<number>(2, [])]));
expect(t.parent(1)).toEqual(null);
expect(t.parent(2)).toEqual(1);
});
it("should return the children of a node", () => {
it('should return the children of a node', () => {
let t = new Tree<any>(new TreeNode<number>(1, [new TreeNode<number>(2, [])]));
expect(t.children(1)).toEqual([2]);
expect(t.children(2)).toEqual([]);
});
it("should return the first child of a node", () => {
it('should return the first child of a node', () => {
let t = new Tree<any>(new TreeNode<number>(1, [new TreeNode<number>(2, [])]));
expect(t.firstChild(1)).toEqual(2);
expect(t.firstChild(2)).toEqual(null);
});
it("should return the path to the root", () => {
it('should return the path to the root', () => {
let t = new Tree<any>(new TreeNode<number>(1, [new TreeNode<number>(2, [])]));
expect(t.pathFromRoot(2)).toEqual([1, 2]);
});
describe("contains", () => {
it("should work", () => {
describe('contains', () => {
it('should work', () => {
let tree = new Tree<any>(
new TreeNode<number>(1, [new TreeNode<number>(2, []), new TreeNode<number>(3, [])]));
let subtree1 = new Tree<any>(new TreeNode<number>(1, []));